AlexxIT/go2rtc · error

expected cmdID 10001, got

Error message

expected cmdID 10001, got %d

What it means

parseK10001 validated the HL magic but the command ID field is not KCmdChallenge (10001), meaning the packet is a different command than the expected auth challenge. The received cmdID is printed; raised during doKAuth.

Solutions

1. Reconnect to restart the K auth handshake from the challenge step
2. Update the parser if the firmware sends a revised challenge command

When it happens

Trigger: Thrown at pkg/wyze/client.go:479 when the library encounters an invalid state.

Common situations: See trigger scenarios.

AI-assisted analysis of AlexxIT/go2rtc@c245815e75 (2026-09-07). Data as JSON: /api/errors/0040c10c4b7355b4. Report an issue: GitHub.

Appendix: source

Thrown at pkg/wyze/client.go:479

	return b
}

func (c *Client) parseK10001(data []byte) (challenge []byte, status byte, err error) {
	if c.verbose {
		fmt.Printf("[Wyze] parseK10001: received %d bytes\n", len(data))
	}

	if len(data) < 33 {
		return nil, 0, fmt.Errorf("data too short: %d bytes", len(data))
	}

	if data[0] != 'H' || data[1] != 'L' {
		return nil, 0, fmt.Errorf("invalid HL magic: %x %x", data[0], data[1])
	}

	cmdID := binary.LittleEndian.Uint16(data[4:])
	if cmdID != KCmdChallenge {
		return nil, 0, fmt.Errorf("expected cmdID 10001, got %d", cmdID)
	}

	status = data[16]
	challenge = make([]byte, 16)
	copy(challenge, data[17:33])

	return challenge, status, nil
}

func (c *Client) parseK10003(data []byte) (*AuthResponse, error) {
	if c.verbose {
		fmt.Printf("[Wyze] parseK10003: received %d bytes\n", len(data))
	}

	if len(data) < 16 {
		return &AuthResponse{}, nil
	}

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