Tencent/APIJSON · error · IllegalArgumentException

join:'${e.getKey()}' 中 ${key} 不合法 !@ APP JOIN 只允许 key@:/Tabl

Error message

join:'${e.getKey()}' 中 ${key} 不合法 !@ APP JOIN 只允许 key@:/Table/refKey 这种 = 等价连接!

What it means

For APP JOIN ('@' join type) with an explicit ON key in the join path, the key minus its trailing '@' must satisfy StringUtil.isName (an English variable name: letter start, letters/digits/underscore). This IllegalArgumentException fires when the key body is not a valid identifier, because APP JOIN only supports simple '=' equivalence joins.

Source

Thrown at APIJSONORM/src/main/java/apijson/orm/AbstractParser.java:1697

			boolean isAppJoin = "@".equals(joinType);

			M refObj = JSON.createJSONObject();

			String key = index < 0 ? null : path.substring(index + 1); // id@
			if (key != null) {  // 指定某个 key 为 JOIN ON 条件
				if (key.indexOf("@") != key.length() - 1) {
					throw new IllegalArgumentException(apijson.JSONRequest.KEY_JOIN + ":" + e.getKey() + " 中 " + key + " 不合法!"
							+ "必须为 &/Table0,</Table1/key1,@/Table1:alias2/key2,... 或 { '&/Table0':{}, '</Table1/key1':{},... } 这种格式!"
							+ "且 Table:alias 的 alias 必须满足英文单词变量名格式!");
				}

				if (tableObj.get(key) instanceof String == false) {
					throw new IllegalArgumentException(apijson.JSONRequest.KEY_JOIN + ":" + e.getKey() + "' 对应的 "
            			+ tableKey + ":{ " + key + ": value } 中 value 类型不合法!必须为同层级引用赋值路径 String!");
				}

				if (isAppJoin && StringUtil.isName(key.substring(0, key.length() - 1)) == false) {
					throw new IllegalArgumentException(apijson.JSONRequest.KEY_JOIN + ":'" + e.getKey() + "' 中 " + key + " 不合法 !" +
							"@ APP JOIN 只允许 key@:/Table/refKey 这种 = 等价连接!");
				}

				refObj.put(key, getString(tableObj, key));
			}


			Set<Entry<String, Object>> tableSet = tableObj.entrySet();
			// 取出所有 join 条件
			M requestObj = JSON.createJSONObject(); // (Map<String, Object>) obj.clone();

			boolean matchSingle = false;
			for (Entry<String, Object> tableEntry : tableSet) {
				String k = tableEntry.getKey();
				Object v = k == null ? null : tableEntry.getValue();
				if (v == null) {
					continue;
				}

View on GitHub (pinned to 5284052872)

Solutions

  1. Rename the join key inside the joined table object and the join path to a plain identifier: letters/digits/underscore, starting with a letter
  2. If the real column has an exotic name, map it via the column alias/dynamic-column mechanism rather than in the join key

Example fix

// before
{ 'join': '@/Comment/to-id@', 'Comment': { 'to-id@': '/User/id' } }
// after
{ 'join': '@/Comment/toId@', 'Comment': { 'toId@': '/User/id' } }
Defensive patterns

Strategy: validation

Validate before calling

const NAME_RE = /^[A-Za-z_][A-Za-z0-9_]*$/;
function checkAppJoinKey(joinPath) {
  const key = joinPath.substring(joinPath.lastIndexOf('/') + 1);
  if (key && key.endsWith('@') && !NAME_RE.test(key.slice(0, -1))) {
    return `APP JOIN ON key '${key}' is not a valid identifier`;
  }
  return null;
}

Type guard

const isValidOnName = (k) => /^[A-Za-z_][A-Za-z0-9_]*@$/.test(k);

Try / catch

Catch IllegalArgumentException containing 'APP JOIN 只允许 key@'; report the offending key from the message and reject the request at the client.

Prevention

When it happens

Trigger: join paths like '@/Comment/to id@' (space), '@/Comment/to-id@' (hyphen), '@/Comment/to@id@' (embedded '@'), or '@/Comment/@' (empty name).

Common situations: Using DB column names with hyphens or non-ASCII characters as join keys; hand-building join path strings via string concatenation that leaves stray characters; copy-paste artifacts (spaces, punctuation) inside the key.

Related errors


AI-assisted analysis of Tencent/APIJSON@5284052872 (2026-08-14). Data as JSON: /api/errors/01cee1a3e98b761b. Report an issue: GitHub.