TheAlgorithms/Java · error · IllegalArgumentException
Matrix A and vector b dimensions do not match.
Error message
Matrix A and vector b dimensions do not match.
What it means
Thrown by ChebyshevIteration.validateInputs when the dimension of vector b does not match the dimension n of matrix A (a.length). The linear system Ax = b requires b to be in R^n where A is n x n. A dimension mismatch means the matrix-vector multiply Av in the residual computation (b - Ax) would fail or produce a meaningless result.
Source
Thrown at src/main/java/com/thealgorithms/maths/ChebyshevIteration.java:99
alphaPrev = alpha;
}
return x; // Return best guess after maxIterations
}
/**
* Validates the inputs for the Chebyshev solver.
*/
private static void validateInputs(double[][] a, double[] b, double[] x0, double minEigenvalue, double maxEigenvalue, int maxIterations, double tolerance) {
int n = a.length;
if (n == 0) {
throw new IllegalArgumentException("Matrix A cannot be empty.");
}
if (n != a[0].length) {
throw new IllegalArgumentException("Matrix A must be square.");
}
if (n != b.length) {
throw new IllegalArgumentException("Matrix A and vector b dimensions do not match.");
}
if (n != x0.length) {
throw new IllegalArgumentException("Matrix A and vector x0 dimensions do not match.");
}
if (minEigenvalue <= 0) {
throw new IllegalArgumentException("Smallest eigenvalue must be positive (matrix must be positive-definite).");
}
if (maxEigenvalue <= minEigenvalue) {
throw new IllegalArgumentException("Max eigenvalue must be strictly greater than min eigenvalue.");
}
if (maxIterations <= 0) {
throw new IllegalArgumentException("Max iterations must be positive.");
}
if (tolerance <= 0) {
throw new IllegalArgumentException("Tolerance must be positive.");
}
}
View on GitHub (pinned to fdfb9a395b)
Solutions
- Ensure b.length == a.length before calling solve.
- Construct b and A from the same dimensional context or validate both against a shared n value.
- Add a precondition: assert b.length == a.length or throw a descriptive error before the call.
Example fix
// before
ChebyshevIteration.solve(new double[3][3], new double[2], new double[3], 1, 2, 100, 1e-6);
// throws 'Matrix A and vector b dimensions do not match.'
// after
int n = a.length;
if (b.length == n) {
double[] x = ChebyshevIteration.solve(a, b, x0, minEig, maxEig, maxIter, tol);
} Defensive patterns
Strategy: validation
Validate before calling
// Validate b dimension matches A before calling solve
int n = a.length;
if (b == null || b.length != n) {
throw new IllegalArgumentException("b.length must equal A's dimension (" + n + ")");
}
double[] x = ChebyshevIteration.solve(a, b, x0, minEig, maxEig, maxIter, tol); Type guard
static boolean dimensionsMatch(double[][] a, double[] b) {
return a != null && a.length > 0 && b != null && b.length == a.length;
} Prevention
- Construct A and b from the same dimensional context or validate both against a shared n.
- Check b after any preprocessing that might resize it.
- Use a combined precondition check for A, b, and x0 dimensions in one place.
When it happens
Trigger: Calling solve with a 3x3 matrix A but b.length == 2 or b.length == 4. For example: solve(new double[3][3], new double[2], new double[3], ...) where b has 2 elements but A has 3 rows.
Common situations: Assembling b from a different data source than A, leading to mismatched dimensions. A preprocessing step that resized b (e.g., adding or removing a boundary condition) without a corresponding change to A. Copy-paste errors where b was built for a different problem size.
Related errors
- Matrix A and vector x0 dimensions do not match.
- Matrix A cannot be empty.
- Matrix A must be square.
- Smallest eigenvalue must be positive (matrix must be positiv
- Max eigenvalue must be strictly greater than min eigenvalue.
AI-assisted analysis of TheAlgorithms/Java@fdfb9a395b (2026-08-13).
Data as JSON: /api/errors/b74ec7675fa73dae.
Report an issue: GitHub.