TheAlgorithms/JavaScript · error · TypeError
One of the items in your array is not a number
Error message
One of the items in your array is not a number
What it means
Thrown as a TypeError by selectionSort() when an element of the input array fails typeof items[i] !== 'number'. Selection sort compares elements with <, so non-numeric elements would produce inconsistent ordering. Note the check runs only in the outer loop over i, so the inner-loop comparison values (items[j]) are not independently type-checked, and the last element is never validated by this loop (it stops at length-1).
Source
Thrown at Sorts/SelectionSort.js:19
/* The selection sort algorithm sorts an array by repeatedly finding the minimum element
*(considering ascending order) from unsorted part and putting it at the beginning. The
*algorithm maintains two subarrays in a given array.
*1) The subarray which is already sorted.
*2) Remaining subarray which is unsorted.
*
*In every iteration of selection sort, the minimum element (considering ascending order)
*from the unsorted subarray is picked and moved to the sorted subarray.
*/
export const selectionSort = (list) => {
if (!Array.isArray(list)) {
throw new TypeError('Given input is not an array')
}
const items = [...list] // We don't want to modify the original array
const length = items.length
for (let i = 0; i < length - 1; i++) {
if (typeof items[i] !== 'number') {
throw new TypeError('One of the items in your array is not a number')
}
// Number of passes
let min = i // min holds the current minimum number position for each pass; i holds the Initial min number
for (let j = i + 1; j < length; j++) {
// Note that j = i + 1 as we only need to go through unsorted array
if (items[j] < items[min]) {
// Compare the numbers
min = j // Change the current min number position if a smaller num is found
}
}
if (min !== i) {
// After each pass, if the current min num != initial min num, exchange the position.
// Swap the numbers
;[items[i], items[min]] = [items[min], items[i]]
}
}
return items
}View on GitHub (pinned to 5c39e87a9a)
Solutions
- Sanitize the array before sorting: arr.filter(x => typeof x === 'number' && !Number.isNaN(x)).
- Coerce elements: arr.map(Number).filter(n => !Number.isNaN(n)).
- Validate at the data source so the array is always numeric.
Example fix
// before const sorted = selectionSort(rawData) // after const clean = rawData.filter(x => typeof x === 'number' && !Number.isNaN(x)) const sorted = selectionSort(clean)
Defensive patterns
Strategy: validation
Validate before calling
function safeSelectionSort(list) {
if (!Array.isArray(list)) throw new TypeError('Expected an array')
const clean = list.filter(x => typeof x === 'number' && !Number.isNaN(x))
return selectionSort(clean)
} Type guard
function isAllNumbers(arr) {
return Array.isArray(arr) && arr.every(x => typeof x === 'number' && !Number.isNaN(x))
} Try / catch
try {
selectionSort(list)
} catch (e) {
if (e instanceof TypeError && e.message.includes('not a number')) {
return selectionSort(list.filter(x => typeof x === 'number' && !Number.isNaN(x)))
}
throw e
} Prevention
- Filter non-numeric and NaN values before sorting.
- Coerce with .map(Number) and drop NaNs.
- Validate element types at the data source.
When it happens
Trigger: Calling selectionSort([3, '1', 2]), selectionSort([1, null, 3]), selectionSort([1, undefined]), selectionSort([5, {x:1}]), or selectionSort([1, NaN]) — note NaN passes typeof but breaks sorting silently.
Common situations: Mixed-type arrays from loose JSON; null/undefined holes from sparse data; values coerced from query strings that include empty strings.
Related errors
- The ${paramName} should be type Number
- Type of n must be number
- Argument is not a number.
- Invalid input, please pass only numbers
- Invalid Input
AI-assisted analysis of TheAlgorithms/JavaScript@5c39e87a9a (2026-08-13).
Data as JSON: /api/errors/5979d0cc00e40e1c.
Report an issue: GitHub.