TheAlgorithms/JavaScript · error · Error

Please provide number greater that 1

Error message

Please provide number greater that 1

What it means

Thrown by `countNumberWordLength(number)` (Project Euler #17) when `number < 1`, AFTER the parseInt check has passed. Note the message contains a typo ('greater that 1' instead of 'greater than 1') and the boundary is exclusive: `number = 1` is allowed. Because the prior parseInt check is loose, strings that parse to integers below 1 (e.g. '0') reach this throw.

Source

Thrown at Project-Euler/Problem017.js:105

 * Validation is performed for input
 * Loop is executed to find total word length for given number range
 * starting from 1
 *
 *
 * @param {number} number
 * @returns {number}
 */
const countNumberWordLength = (number) => {
  let count = 0

  // Not a number check
  if (Number.isNaN(parseInt(number))) {
    throw new Error('Invalid input, please provide valid number')
  }

  // Number should be greater than 1
  if (number < 1) {
    throw new Error('Please provide number greater that 1')
  }

  // Loop to calculate word length by calling {@link numberToWord}
  for (let i = 1; i <= number; i++) {
    count += numberToWordLength(i)
  }

  // return final count for number word length
  return count
}

export { countNumberWordLength }

View on GitHub (pinned to 5c39e87a9a)

Solutions

1. Validate `number >= 1` (decide explicitly whether 1 is valid for your use case).
2. Coerce strictly with `Number(...)` and `Number.isInteger` rather than relying on parseInt.
3. Note the message typo if you surface it to users - reword before display.

Example fix

// before
countNumberWordLength(n) // n could be 0

// after
const num = Number(n)
if (!Number.isInteger(num) || num < 1) throw new RangeError('number must be a positive integer >= 1')
countNumberWordLength(num)

const n = Number(number)
if (!Number.isInteger(n) || n < 1) {
  throw new RangeError('number must be an integer >= 1')
}
countNumberWordLength(n)

const isPositiveInt = (x) => typeof x === 'number' && Number.isInteger(x) && x >= 1

When it happens

Trigger: Call `countNumberWordLength(0)`, `countNumberWordLength(-3)`, `countNumberWordLength('0')`. `number = 1` passes and returns the length of 'one'.

Common situations: Off-by-one in upper-bound loops, defaulting a 'count up to N' field to 0, or arithmetic that produced a negative result.

Related errors

• No natural numbers exist below 1
• Fibonacci sequence limit can't be less than 1
• Invalid Input
• Invalid Input
• Dimension must be odd

AI-assisted analysis of TheAlgorithms/JavaScript@5c39e87a9a (2026-08-13). Data as JSON: /api/errors/df8728f70fcb5720. Report an issue: GitHub.