apache/beam · error · KeyError
label
Error message
label
What it means
In the deferred groupby implementation, when grouping 'by' a concrete NumPy ndarray, this WontImplementError fires: the message/label field identifies the unsupported operation because grouping by a raw ndarray is order-sensitive, which the Beam DataFrame API cannot guarantee under its partitioning semantics. Use a named column or list of columns instead.
Source
Thrown at sdks/python/apache_beam/dataframe/frames.py:522
grouping_columns = []
grouping_indexes = [0]
elif isinstance(by, np.ndarray):
raise frame_base.WontImplementError(
"Grouping by a concrete ndarray is order sensitive.",
reason="order-sensitive")
elif isinstance(self, DeferredDataFrame):
if not isinstance(by, list):
by = [by]
# Find the columns that we need to move into the index so we can group by
# them
column_names = self._expr.proxy().columns
grouping_columns = list(set(by).intersection(column_names))
index_names = self._expr.proxy().index.names
for label in by:
if label not in index_names and label not in self._expr.proxy().columns:
raise KeyError(label)
grouping_indexes = list(set(by).intersection(index_names))
if grouping_indexes:
if set(by) == set(index_names):
to_group = self._expr
elif set(by).issubset(index_names):
to_group = self.droplevel(index_names.difference(by))._expr
else:
to_group = self.reset_index(grouping_indexes).set_index(by)._expr
else:
to_group = self.set_index(by)._expr
if grouping_columns:
# TODO(https://github.com/apache/beam/issues/20759):
# It should be possible to do this without creating
# an expression manually, by using DeferredDataFrame.set_index, i.e.:
# to_group_with_index = self.set_index([self.index] +
# grouping_columns)._exprView on GitHub (pinned to 12126d8942)
Solutions
- Fix the label spelling to match an actual column or index name
- Verify available keys with df.columns and df.index.names before grouping
- Select only the columns that exist: by=[c for c in wanted if c in df.columns]
Example fix
// before
df.groupby('Counrty')
// after
assert 'country' in df.columns
df.groupby('country') Defensive patterns
Strategy: validation
Validate before calling
cols = set(df.columns) | set(df.index.names)
missing = [b for b in by if b not in cols]
if missing:
raise KeyError(f"groupby keys not found: {missing}; have {sorted(cols)}") Type guard
def keys_exist(df, by):
names = set(df.columns) | set(df.index.names)
return all(b in names for b in (by if isinstance(by, (list, tuple)) else [by])) Try / catch
try:
out = df.groupby(by)
except KeyError as e:
logging.error("unknown groupby key %s; columns=%s index=%s", e, list(df.columns), list(df.index.names))
raise Prevention
- Verify by labels against df.columns and df.index.names
- Watch for schema drift from upstream transforms
- Mind case sensitivity in column names
When it happens
Trigger: df.groupby('countrys') (typo) where the column is named 'country'; by list containing a label renamed upstream; grouping by a label that only exists after a previous transformation that was dropped.
Common situations: Schema drift after upstream pipeline changes; case-sensitivity mistakes ('Date' vs 'date'); grouping by a MultiIndex level name that was dropped by an earlier reset_index/droplevel.
Understand the failure class
Background: 'Could not be found', 'does not exist', 'not found in database': the resource-not-found family when an ID, slug, key, or URI lookup comes back empty — this error's family across 20 libraries.
Related errors
- k_val
- Cannot specify both 'labels' and 'index'/'columns'
- axis must be one of (0, 1, 'index', 'columns'), got '%s'
- groupby(as_index=False)
- You have to supply one of 'by' and 'level'
AI-assisted analysis of apache/beam@12126d8942 (2026-09-13).
Data as JSON: /api/errors/dcd79e729f0f0cde.
Report an issue: GitHub.