apache/superset · error · ReportScheduleUnexpectedError

Report schedule unexpected error

Error message

Report schedule unexpected error

What it means

Error "Report schedule unexpected error" thrown in apache/superset.

Source

Thrown at superset/commands/report/execute.py:2187

                    str(ex) or type(ex).__name__,
                    type(ex).__name__,
                    report_execution_context,
                )
            raise
        except Exception as ex:
            if (
                self._model
                and self._model.type == ReportScheduleType.REPORT
                and owns_report_working_state
            ):
                persist_owned_report_execution_terminal_error(
                    self._model.id,
                    self._execution_id,
                    str(ex) or type(ex).__name__,
                    type(ex).__name__,
                    report_execution_context,
                )
            raise ReportScheduleUnexpectedError(str(ex)) from ex

    def validate(self) -> None:
        # Validate/populate model exists
        logger.info(
            "session is validated: id %s, executionid: %s",
            self._model_id,
            self._execution_id,
        )
        self._model = (
            db.session.query(ReportSchedule).filter_by(id=self._model_id).one_or_none()
        )
        if not self._model:
            raise ReportScheduleNotFoundError()

View on GitHub (pinned to f4587218dd)

Solutions

1. Inspect worker logs for the unexpected exception and retry the schedule after resolving it.

When it happens

Trigger: An unhandled exception occurs while finalizing a report schedule run.

Common situations: Celery report task raises an unexpected error not classified as a system or client error.

AI-assisted analysis of apache/superset@f4587218dd (2026-08-14). Data as JSON: /api/errors/5b2e5e53a59aa1e2. Report an issue: GitHub.