jestjs/jest · error · TypeError

@jest/diff-sequences: ${name} typeof ${typeof arg} is not a

Error message

@jest/diff-sequences: ${name} typeof ${typeof arg} is not a number

What it means

diffSequence(aLength, bLength, isCommon, foundSubsequence) calls validateLength on each length. The first guard requires `typeof arg === 'number'`; anything else (undefined, string, null, object) throws TypeError. This is a hard precondition because the algorithm indexes into sequences 0..length and cannot proceed on a non-numeric length.

Source

Thrown at packages/diff-sequences/src/index.ts:761

    // Recursely find and return common subsequences following the division.
    findSubsequences(
      nChangeFollowing,
      aStartFollowing,
      aEnd,
      bStartFollowing,
      bEnd,
      transposed,
      callbacks,
      aIndexesF,
      aIndexesR,
      division,
    );
  }
};

const validateLength = (name: string, arg: unknown) => {
  if (typeof arg !== 'number') {
    throw new TypeError(`${pkg}: ${name} typeof ${typeof arg} is not a number`);
  }
  if (!Number.isSafeInteger(arg)) {
    throw new RangeError(`${pkg}: ${name} value ${arg} is not a safe integer`);
  }
  if (arg < 0) {
    throw new RangeError(`${pkg}: ${name} value ${arg} is a negative integer`);
  }
};

const validateCallback = (name: string, arg: unknown) => {
  const type = typeof arg;
  if (type !== 'function') {
    throw new TypeError(`${pkg}: ${name} typeof ${type} is not a function`);
  }
};

// Compare items in two sequences to find a longest common subsequence.
// Given lengths of sequences and input function to compare items at indexes,

View on GitHub (pinned to f49721c78e)

Solutions

  1. Pass the actual numeric lengths, typically `a.length` and `b.length` of the two arrays/strings.
  2. Add an explicit coercion or guard at the call site: `Number.isFinite(x) ? x : 0`.
  3. Re-order arguments to match the signature (aLength, bLength, isCommon, foundSubsequence).

Example fix

// before
diffSequence(arr.length, other.length, 'isCommon', cb); // 3rd arg wrong, but length-like; real bug:
diffSequence(undefined, other.length, isCommon, foundSubsequence);

// after
diffSequence(arr.length, other.length, isCommon, foundSubsequence);
Defensive patterns

Strategy: type-guard

Validate before calling

if (typeof aLength !== 'number' || typeof bLength !== 'number') {
  throw new TypeError('diffSequence lengths must be numbers');
}
diffSequence(aLength, bLength, isCommon, foundSubsequence);

Type guard

function isLength(x: unknown): x is number {
  return typeof x === 'number' && Number.isSafeInteger(x) && x >= 0;
}

Try / catch

try {
  diffSequence(aLength, bLength, isCommon, foundSubsequence);
} catch (e) {
  if (e instanceof TypeError && /is not a number/.test(e.message)) { /* coerce or reject */ }
  throw e;
}

Prevention

When it happens

Trigger: Calling diffSequence with aLength or bLength that is not a number: passing `undefined` (forgot an argument), a string like '"5"', null, or an object. Direct internal calls in Jest's diff/output code that mistakenly forward an uncomputed length also land here.

Common situations: Wrapping @jest/diff-sequences to build a custom differ and forgetting to coerce Array.length; refactoring that swaps argument order; passing a getter result that returned undefined.

Related errors


AI-assisted analysis of jestjs/jest@f49721c78e (2026-08-03). Data as JSON: /data/errors/6fa83d0344975293.json. Report an issue: GitHub.