pandas-dev/pandas · error · TypeError

Cannot multiply '{self.dtype}' by bool, explicitly cast to i

Error message

Cannot multiply '{self.dtype}' by bool, explicitly cast to integers instead

What it means

Raised by TimedeltaArray.__mul__ when the scalar operand is a Python/numpy bool (GH#58054). Multiplying a duration by True/False is almost always a bug (True repeats once, False yields zero-length/NaT), so pandas requires an explicit integer cast to make intent clear. The same restriction applies to bool-dtype arrays (line 545). This aligns with numpy's deprecation of bool*number arithmetic.

Source

Thrown at pandas/core/arrays/timedeltas.py:502

            i8_result[nat_out] = iNaT
        result = i8_result.view(self._ndarray.dtype)
        return type(self)._simple_new(result, dtype=result.dtype)

    def _mul_int_overflowsafe(self, i8_other: npt.NDArray[np.int64]) -> Self:
        # GH#43178: mul_overflowsafe raises the low-level OverflowError; surface
        #  it as OutOfBoundsTimedelta to match pandas' other td64 overflow paths.
        try:
            i8_result = mul_overflowsafe(self.asi8, i8_other)
        except OverflowError as err:
            raise OutOfBoundsTimedelta("Overflow in int64 multiplication") from err
        result = i8_result.view(self._ndarray.dtype)
        return type(self)._simple_new(result, dtype=result.dtype)

    @unpack_zerodim_and_defer("__mul__")
    def __mul__(self, other) -> Self:
        if is_scalar(other):
            if lib.is_bool(other):
                raise TypeError(
                    f"Cannot multiply '{self.dtype}' by bool, explicitly cast to "
                    "integers instead"
                )
            if lib.is_integer(other):
                # GH#43178: detect int64 overflow rather than silently wrapping
                #  in the i8 cast below (e.g. a multiplier outside int64 bounds).
                # TODO(numpy>=2.5): numpy detects this natively (numpy GH-31378)
                #  but raises OverflowError; once the numpy floor is >= 2.5, drop
                #  mul_overflowsafe and re-wrap numpy's error as
                #  OutOfBoundsTimedelta. The float path isn't covered and stays.
                other = int(other)
                if other > lib.i8max or other < -lib.i8max - 1:
                    raise OutOfBoundsTimedelta("Overflow in int64 multiplication")
                i8_vals = self.asi8
                if other != 0 and i8_vals.size:
                    # The extreme elements bound all products, so checking them
                    #  with exact Python-int arithmetic lets the common
                    #  no-overflow case use a vectorized multiply. NaT

View on GitHub (pinned to 71959b8cb9)

Solutions

  1. Cast the bool to int: `td_arr * mask.astype('int64')` or `td_arr * int(mask)`.
  2. If you meant filtering, use boolean indexing `td_arr[mask]` instead of multiplication.
  3. Replace bool-as-multiplier logic with np.where if you need conditional scaling.

Example fix

# before
td_arr * (td_arr > pd.Timedelta(0))  # TypeError
# after
td_arr * (td_arr > pd.Timedelta(0)).astype('int64')
Defensive patterns

Strategy: type-guard

Validate before calling

from pandas._libs import lib

def safe_td_mul(td_arr, other):
    if lib.is_bool(other) or (hasattr(other, 'dtype') and other.dtype.kind == 'b'):
        other = other.astype('int64') if hasattr(other, 'astype') else int(other)
    return td_arr * other

Type guard

from pandas._libs import lib
def is_bool_operand(other) -> bool:
    if lib.is_bool(other):
        return True
    dt = getattr(other, 'dtype', None)
    return dt is not None and dt.kind == 'b'

Try / catch

try:
    return td_arr * mask
except TypeError as e:
    if 'Cannot multiply' in str(e) and 'bool' in str(e):
        return td_arr * mask.astype('int64')
    raise

Prevention

When it happens

Trigger: Executing `td_arr * True`, `td_arr * np.bool_(False)`, or `td_arr * bool_series`. The scalar check at timedeltas.py:501 uses lib.is_bool(other); the array check at line 543 uses other.dtype.kind=='b'.

Common situations: Using a boolean mask as a multiplier instead of as a selector; piping comparison results into arithmetic; legacy code relying on implicit bool-to-int coercion.

Related errors


AI-assisted analysis of pandas-dev/pandas@71959b8cb9 (2026-08-07). Data as JSON: /api/errors/e75367a212290305. Report an issue: GitHub.