pandas-dev/pandas · error · OutOfBoundsTimedelta

Overflow in timedelta multiplication

Error message

Overflow in timedelta multiplication

What it means

Raised by TimedeltaArray._mul_float_overflowsafe when multiplying a timedelta64 array by a float whose products would exceed the int64 nanosecond range (~±292 years). Because numpy's int64-backed timedelta silently saturates at int64.max, pandas pre-checks the float64 product against 2**63 (not i8max, since i8max rounds up to 2**63 in float64) and raises OutOfBoundsTimedelta instead. NaT positions and NaN products are masked out before the bound check.

Solutions

  1. Reduce the multiplier so all products stay within ±2**63 nanoseconds (~292.3 years from zero).
  2. Convert the timedelta to a coarser representation (e.g. compute in seconds via `.dt.total_seconds()`) before scaling, then cast back if needed.
  3. Cap or clip extreme source values with `.clip()` before multiplication.

Example fix

# before
pd.to_timedelta(10**17, unit='ns') * 1e6  # OutOfBoundsTimedelta

# after
(pd.to_timedelta(10**17, unit='ns') / 1e6).total_seconds()
Defensive patterns

Strategy: validation

Validate before calling

import numpy as np

NS_INT64_MAX = 2**63

def td_float_mul_is_safe(td_ns_values, factor):
    arr = np.asarray(td_ns_values, dtype='i8')
    arr = np.where(arr == np.int64(np.iinfo(np.int64).min), 0, arr)
    return np.max(np.abs(arr.astype('f8') * factor), initial=0.0) < NS_INT64_MAX

Type guard

null

Try / catch

from pandas.errors import OutOfBoundsTimedelta
try:
    result = td * factor
except OutOfBoundsTimedelta:
    # operate in coarser units to avoid the ns int64 ceiling
    result = (td.dt.total_seconds() * factor)

Prevention

When it happens

Trigger: Multiplying a large-magnitude timedelta by a large float: `pd.to_timedelta(10**17, unit='ns') * 1e6`, or scaling a long-duration Series by a float that pushes any element past ±2**63 nanoseconds.

Common situations: Unit-conversion arithmetic that accidentally uses ns-resolution magnitudes; aggregating or rescaling long durations (days/weeks) by large float weights.

Related errors


AI-assisted analysis of pandas-dev/pandas@3b7651241d (2026-08-11). Data as JSON: /api/errors/1ab8e29e7f3fd08b. Report an issue: GitHub.

Appendix: source

Thrown at pandas/core/arrays/timedeltas.py:494

    def _mul_float_overflowsafe(
        self, other: float | np.floating | npt.NDArray[np.floating]
    ) -> Self:
        # GH#43178: detect float products that would silently saturate to
        #  int64.max on the int64 cast below
        i8 = self.asi8
        self_mask = i8 == iNaT
        if self_mask.any():
            # zero out NaT positions so they don't trigger the bounds check
            i8 = np.where(self_mask, 0, i8)
        f_result = i8 * other
        nan_mask = np.isnan(f_result)
        non_nan = f_result[~nan_mask]
        # Compare against 2**63, not i8max: i8max (2**63 - 1) rounds up to
        #  2**63 in float64, so a product landing exactly on 2**63 would slip
        #  past a ``> i8max`` check and saturate on the cast. Also catches +/-inf.
        if non_nan.size and np.max(np.abs(non_nan), initial=0.0) >= 2.0**63:
            raise OutOfBoundsTimedelta("Overflow in timedelta multiplication")
        # NaN-to-int cast is platform-dependent; substitute 0 then re-mask as NaT
        if nan_mask.any():
            f_result = np.where(nan_mask, 0.0, f_result)
        i8_result = f_result.astype("i8")
        nat_out = self_mask | nan_mask
        if nat_out.any():
            i8_result[nat_out] = iNaT
        result = i8_result.view(self._ndarray.dtype)
        return type(self)._simple_new(result, dtype=result.dtype)

    def _mul_int_overflowsafe(self, i8_other: npt.NDArray[np.int64]) -> Self:
        # GH#43178: mul_overflowsafe raises the low-level OverflowError; surface
        #  it as OutOfBoundsTimedelta to match pandas' other td64 overflow paths.
        try:
            i8_result = mul_overflowsafe(self.asi8, i8_other)
        except OverflowError as err:
            raise OutOfBoundsTimedelta("Overflow in int64 multiplication") from err
        result = i8_result.view(self._ndarray.dtype)

View on GitHub (pinned to 3b7651241d)